CVE-2025-38305
In the Linux kernel, the following vulnerability has been resolved:
ptp: remove ptp->n_vclocks check logic in ptp_vclock_in_use()
There is no disagreement that we should check both ptp->is_virtual_clock and ptp->n_vclocks to check if the ptp virtual clock is in use.
However, when we acquire ptp->n_vclocks_mux to read ptp->n_vclocks in ptp_vclock_in_use(), we observe a recursive lock in the call trace starting from n_vclocks_store().
============================================ WARNING: possible recursive locking detected 6.15.0-rc6 #1 Not tainted -------------------------------------------- syz.0.1540/13807 is trying to acquire lock: ffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at: ptp_vclock_in_use drivers/ptp/ptp_private.h:103 [inline] ffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at: ptp_clock_unregister+0x21/0x250 drivers/ptp/ptp_clock.c:415
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other info that might help us debug this: Possible unsafe locking scenario:
*** DEADLOCK *** .... ============================================
The best way to solve this is to remove the logic that checks ptp->n_vclocks in ptp_vclock_in_use().
The reason why this is appropriate is that any path that uses ptp->n_vclocks must unconditionally check if ptp->n_vclocks is greater than 0 before unregistering vclocks, and all functions are already written this way. And in the function that uses ptp->n_vclocks, we already get ptp->n_vclocks_mux before unregistering vclocks.
Therefore, we need to remove the redundant check for ptp->n_vclocks in ptp_vclock_in_use() to prevent recursive locking.
Detalles técnicos trazas, registros y código del informe original
but task is already holding lock:
ffff888030704868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at:
n_vclocks_store+0xf1/0x6d0 drivers/ptp/ptp_sysfs.c:215
CPU0
----
lock(&ptp->n_vclocks_mux);
lock(&ptp->n_vclocks_mux);CVSS
- Versión: 3.1
- Vector: CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:N/I:N/A:H
- Puntuación base: 5.5
Probabilidad de explotación (EPSS)
- Probabilidad de explotación en los próximos 30 días: 0.17%
- Percentil entre todas las CVEs puntuadas: 5
- Fecha de la puntuación: 5/10/2026
EPSS (Exploit Prediction Scoring System, de FIRST) estima la probabilidad de que una vulnerabilidad sea explotada en 30 días. Complementa a CVSS (impacto) y a CISA KEV (explotación confirmada).
Tecnologías afectadas (2)
CWE
- NVD-CWE-noinfo
Referencias
- https://git.kernel.org/stable/c/259119595227fd20f6aa29d85abe086b6fdd9eb1
- https://git.kernel.org/stable/c/5d217e7031a5c06d366580fc6ddbf43527b780d4
- https://git.kernel.org/stable/c/87f7ce260a3c838b49e1dc1ceedf1006795157a2
- https://git.kernel.org/stable/c/b1b73c452331451020be3bf4b014901015ae6663
- https://git.kernel.org/stable/c/b93e6fef4eda48e17d9c642b9abad98a066fd4a3
- https://git.kernel.org/stable/c/ef8fc007c28a30a4c0d90bf755e0f343d99bb392
- https://lists.debian.org/debian-lts-announce/2025/10/msg00008.html
JSON original (NVD)
Mostrar
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"value": "In the Linux kernel, the following vulnerability has been resolved:\n\nptp: remove ptp->n_vclocks check logic in ptp_vclock_in_use()\n\nThere is no disagreement that we should check both ptp->is_virtual_clock\nand ptp->n_vclocks to check if the ptp virtual clock is in use.\n\nHowever, when we acquire ptp->n_vclocks_mux to read ptp->n_vclocks in\nptp_vclock_in_use(), we observe a recursive lock in the call trace\nstarting from n_vclocks_store().\n\n============================================\nWARNING: possible recursive locking detected\n6.15.0-rc6 #1 Not tainted\n--------------------------------------------\nsyz.0.1540/13807 is trying to acquire lock:\nffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at:\n ptp_vclock_in_use drivers/ptp/ptp_private.h:103 [inline]\nffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at:\n ptp_clock_unregister+0x21/0x250 drivers/ptp/ptp_clock.c:415\n\nbut task is already holding lock:\nffff888030704868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, at:\n n_vclocks_store+0xf1/0x6d0 drivers/ptp/ptp_sysfs.c:215\n\nother info that might help us debug this:\n Possible unsafe locking scenario:\n\n CPU0\n ----\n lock(&ptp->n_vclocks_mux);\n lock(&ptp->n_vclocks_mux);\n\n *** DEADLOCK ***\n....\n============================================\n\nThe best way to solve this is to remove the logic that checks\nptp->n_vclocks in ptp_vclock_in_use().\n\nThe reason why this is appropriate is that any path that uses\nptp->n_vclocks must unconditionally check if ptp->n_vclocks is greater\nthan 0 before unregistering vclocks, and all functions are already\nwritten this way. And in the function that uses ptp->n_vclocks, we\nalready get ptp->n_vclocks_mux before unregistering vclocks.\n\nTherefore, we need to remove the redundant check for ptp->n_vclocks in\nptp_vclock_in_use() to prevent recursive locking."
},
{
"lang": "es",
"value": "En el kernel de Linux, se ha resuelto la siguiente vulnerabilidad: ptp: eliminar la lógica de comprobación de ptp->n_vclocks en ptp_vclock_in_use(). No hay desacuerdo en que debemos comprobar tanto ptp->is_virtual_clock como ptp->n_vclocks para comprobar si el reloj virtual ptp está en uso. Sin embargo, al adquirir ptp->n_vclocks_mux para leer ptp->n_vclocks en ptp_vclock_in_use(), observamos un bloqueo recursivo en el seguimiento de llamadas a partir de n_vclocks_store(). ============================================== ADVERTENCIA: posible bloqueo recursivo detectado 6.15.0-rc6 #1 No contaminado -------------------------------------------- syz.0.1540/13807 está intentando adquirir el bloqueo: ffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, en: ptp_vclock_in_use drivers/ptp/ptp_private.h:103 [en línea] ffff888035a24868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, en: ptp_clock_unregister+0x21/0x250 drivers/ptp/ptp_clock.c:415 pero la tarea ya tiene el bloqueo: ffff888030704868 (&ptp->n_vclocks_mux){+.+.}-{4:4}, en: n_vclocks_store+0xf1/0x6d0 drivers/ptp/ptp_sysfs.c:215 otra información que podría ayudarnos a depurar esto: Posible escenario de bloqueo inseguro: CPU0 ---- lock(&ptp->n_vclocks_mux); lock(&ptp->n_vclocks_mux); *** BLOQUEO INTERMEDIO *** .... ============================================== La mejor manera de resolver esto es eliminar la lógica que comprueba ptp->n_vclocks en ptp_vclock_in_use(). Esto es apropiado porque cualquier ruta que use ptp->n_vclocks debe comprobar incondicionalmente si ptp->n_vclocks es mayor que 0 antes de anular el registro de vclocks, y todas las funciones ya están escritas de esta manera. En la función que usa ptp->n_vclocks, ya obtenemos ptp->n_vclocks_mux antes de anular el registro de vclocks. Por lo tanto, necesitamos eliminar la comprobación redundante de ptp->n_vclocks en ptp_vclock_in_use() para evitar el bloqueo recursivo."
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"lastModified": "2026-06-17T09:16:35.237",
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